How do you find the equation of a line with slope of -3 and contains the point (0, -3)?

Answer 1

#y=-3x-3#

Formula for a line: #y=ax+b# #a# represents slope which is #-3# #y=-3x+b# Then we know this line must go through the point (0,-3). So x=0 and y=-3. Let's substitute and find the value of #b#
#-3=-3*0+b# #-3=b# and finally we have everything we need: #y=-3x-3#
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Answer 2

Use the point-slope form of a linear equation: y - y₁ = m(x - x₁), where (x₁, y₁) is the given point and m is the slope. Then substitute the given values into the equation and simplify to find the equation of the line.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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