# How do you find the equation of a line tangent to the function #y=4x-x^2# at (2,4)?

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To find the equation of a line tangent to the function y=4x-x^2 at (2,4), we need to find the slope of the tangent line at that point.

To find the slope, we take the derivative of the function y=4x-x^2 with respect to x.

The derivative of y=4x-x^2 is dy/dx = 4 - 2x.

Substituting x=2 into the derivative, we get dy/dx = 4 - 2(2) = 4 - 4 = 0.

Since the slope of the tangent line is 0, the equation of the tangent line is y = 4.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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