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How do you find the equation given (4, 6) and slope 3/2?

Answer 1

Savannah Anderson

The equation of the line in slope-intercept form is
#y=3/2x#

We can use the point-slope formula #y-y_1=m(x-x_1)#

Given the point (4,6) and the slope of #3/2#

#m=3/2# #x_1=4# #y_1=6#

Plug in the values and simplify

#y-6=3/2(x-4)#

Distribute the slope

#y-6=3/2x-6#

Use additive inverse to isolate the #y#

#y cancel(-6) cancel(+6) = 3/2x cancel(-6) cancel(+6)#

The equation of the line in slope-intercept form is #y=3/2x#

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Answer 2

Savannah Anderson

You can use the point-slope form of a linear equation: ( y - y_1 = m(x - x_1) ), where ( m ) is the slope and ( (x_1, y_1) ) is a point on the line. Plugging in the values ( (4, 6) ) for ( (x_1, y_1) ) and ( \frac{3}{2} ) for the slope ( m ), you get: ( y - 6 = \frac{3}{2}(x - 4) ). Simplify to get the equation in slope-intercept form, ( y = mx + b ), where ( b ) is the y-intercept.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.