How do you find the equation for the line passing through (2,1) with slope 5/2?

Answer 1

It is #y=5/2x-4#

The formula for the line is #y=m*x+b# where #m=5/2# hence
#y=5/2x+b# since point (2,1) satisfies the equation
#1=5/2*2+b=>b=-4# hence the line is
#y=5/2x-4#
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Answer 2

To find the equation for the line passing through the point (2,1) with slope 5/2, you can use the point-slope form of a linear equation. The point-slope form is y - y1 = m(x - x1), where (x1, y1) is the given point and m is the slope.

Substituting the values into the formula:

y - 1 = (5/2)(x - 2)

Simplify:

y - 1 = (5/2)x - 5

Add 1 to both sides:

y = (5/2)x - 4

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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