# How do you find the domain of #y=sqrt(x^2 - 6 x + 5)#?

The domain is

Therefore,

We factorise the inequality

We build a sign chart

Therefore,

graph{sqrt(x^2-6x+5) [-10, 10, -5, 5]}

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To find the domain of the function (y = \sqrt{x^2 - 6x + 5}), you need to consider the values of (x) for which the expression inside the square root is valid. Since taking the square root of a negative number is undefined in the real number system, the expression inside the square root must be non-negative.

So, you need to solve the inequality (x^2 - 6x + 5 \geq 0) to find the values of (x) that make the expression non-negative. Once you find the solutions to this inequality, those values of (x) will be the domain of the function.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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