# How do you find the domain of # sqrt(x + 5) #?

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To find the domain of ( \sqrt{x + 5} ), the expression inside the square root must be greater than or equal to zero. So, ( x + 5 \geq 0 ). Solving for ( x ), we get ( x \geq -5 ). Therefore, the domain of ( \sqrt{x + 5} ) is all real numbers greater than or equal to -5.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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