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How do you find the domain of #p(x)=x^2+4#?

Answer 1

There are no restrictions in the argument of the function, so the domain is #x in(-ooto+oo)#

The range is another story. Since #x^2>=0#: #p(x) in[4to+oo)# (the square bracket meaning "inclusive") graph{x^2+4 [-16.28, 15.76, -2.5, 13.52]}

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Answer 2

Eli Assouline

The domain of ( p(x) = x^2 + 4 ) is all real numbers.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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