How do you find the domain of #f (x) = sqrt (-x + 9)#?
Eva AdamsonSince a negative number cannot be found under square root, the answer is:
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Set the expression inside the square root greater than or equal to zero and solve for x. Domain: -x + 9 ≥ 0, which yields x ≤ 9. Therefore, the domain of f(x) is x ≤ 9.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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