How do you find the domain of #f(x)=sqrt(x+4)#?

Answer 1

#x in [-4, +oo[#

Since you have a square root, the function it contains needs to be greater than or equal to zero:

#x+4>=0#
#x>=-4#
#x in [-4, +oo[#
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Answer 2

To find the domain of ( f(x) = \sqrt{x+4} ), set the expression under the square root greater than or equal to zero:

[ x + 4 \geq 0 ]

Solve for ( x ):

[ x \geq -4 ]

So, the domain of ( f(x) ) is all real numbers greater than or equal to -4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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