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How do you find the domain of #f(x) =3sqrt(6x + 42)#?

Answer 1

Genesis Allen

#[-7,+oo)#

#"the domain is determined by the radical"#

#"that is "#

#6x+42>=0rArrx>=-7#

#rArr" domain is "[-7,+oo)# graph{3sqrt(6x+42) [-10, 10, -5, 5]}

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Answer 2

Nathan Axel

To find the domain of (f(x) = 3\sqrt{6x + 42}), the expression inside the square root ((6x + 42)) must be greater than or equal to zero. Solve (6x + 42 \geq 0) for (x).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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