# How do you find the domain for #1/(x-3)#?

everywhere where x - 3 is not zero :)

if x-3 is zero, the function blows up. So anywhere else. it is well-defined. The domain is thus the real axis minus the point x=3

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To find the domain of ( \frac{1}{x-3} ), identify any values of ( x ) that would make the denominator equal to zero. In this case, ( x-3 ) cannot equal zero, so the domain consists of all real numbers except ( x = 3 ). Therefore, the domain is ( {x \in \mathbb{R} : x \neq 3} ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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