How do you find the domain and range of #y=x^2 +2x -5#?

Answer 1

Domain: #(-oo, +oo)#
Range: #[-6, +oo)#

#y=x^2+2x-5#
#y# is defined #forall x in RR# Hence the domain of #y# is #(-oo, +oo)#
#y# is a quadratic function of the form #ax^2+bx+c#
The graph of #y# is a parabola with vertex where #x=(-b)/(2a)#
Since the coefficient of #x^2>0# the vertex will be the absolute minimum of #y#
At the vertex #x= (-2)/(2xx1) = -1#
#:. y_min = y(-1) = 1-2-5 = -6#
Since #y# has no upper bound the range of #y# is [-6, +oo)
As can be seen on the graph of #y# below.

x^2 + 2x-5 = [-16.02, 16.02, -8.01, 8.01]}

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Answer 2

To find the domain and range of the function ( y = x^2 + 2x - 5 ), you need to consider the possible values of ( x ) that make the function defined, and the corresponding values of ( y ) that the function can take.

Domain: Since ( y = x^2 + 2x - 5 ) is a polynomial function, it is defined for all real numbers. Therefore, the domain of the function is all real numbers.

Range: To find the range, you can analyze the behavior of the quadratic function. The function ( y = x^2 + 2x - 5 ) is a quadratic function, and its graph is a parabola opening upwards because the coefficient of ( x^2 ) is positive.

The minimum or maximum value of the quadratic function occurs at the vertex of the parabola. You can find the x-coordinate of the vertex using the formula ( x = \frac{-b}{2a} ), where ( a ) and ( b ) are the coefficients of ( x^2 ) and ( x ) respectively in the quadratic equation ( y = ax^2 + bx + c ).

In this case, ( a = 1 ) and ( b = 2 ), so ( x = \frac{-2}{2} = -1 ).

Now, substitute ( x = -1 ) into the function to find the corresponding value of ( y ): ( y = (-1)^2 + 2(-1) - 5 = 1 - 2 - 5 = -6 )

So, the vertex of the parabola is at the point ( (-1, -6) ). Since the parabola opens upwards, the minimum value of ( y ) occurs at the vertex, and the range of the function is all real numbers greater than or equal to the y-coordinate of the vertex.

Therefore, the range of the function ( y = x^2 + 2x - 5 ) is ( y \geq -6 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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