# How do you find the domain and range of #y = sqrt(x+8)#?

Domain is

Range is

First, let's examine the equation.

We are interested in the values of x for the domain that result in a "valid result".

Alternatively put, we're searching for x values that won't "break" the equation.

We can therefore set this up.

To obtain, subtract 8 from each side.

Let's talk about the range now.

It's important to remember that the square root symbol only denotes the positive root in this case. For instance,

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The domain of y = √(x + 8) is x ≥ -8, and the range is y ≥ 0.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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