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How do you find the domain and range of # y= sqrt (x+4)/x#?

Answer 1

Domain is any real value with # x >= -4 and x != 0#
Range is any real value except #0#.

#y =sqrt (x+4)/x#. for finding domain under root should not be less than zero and denominator should not be zero. Domain: # (x+4) >= 0 or x >= -4 and x != 0#

Domain (value of x) is any real value with # x >= -4 and x != 0# Range (value of y) is any real value except #0#. graph{(x+4)^0.5/x [-10, 10, -5, 5]}

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Answer 2

Avery Alexander

Domain: ( x \neq -4 ), Range: ( y > 0 )

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.