How do you find the domain and range of #x^5-2x^3+1#?

Answer 1

The domain and range are both the whole of #RR#, i.e. #(-oo, oo)#

Any polynomial #f(x)# in #x# is well defined for all #x in RR#, so the domain is #RR#.
For any polynomial #f(x)#, as #x# gets larger, the term with highest degree tends to dominate.
So if #f(x)# is of odd degree with positive leading coefficient (as in our example), then:
As #x# gets large and negative #f(x)# gets large and negative.
As #x# gets large and positive #f(x)# gets large and positive.

Polynomials are also continuous (no breaks in the graph).

As a result, the graph of #f(x)# will intersect any horizontal line - that is, given any #y in RR#, there is an #x in RR# for which #f(x) = y#.
Hence the range is also the whole of #RR#.

graph{(x^5-2x^3+1-y)(y - 3.2) = 0 [-10, 10, -5, 5]}

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Answer 2

Domain: All real numbers Range: All real numbers

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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