How do you find the domain and range of #sqrt(x-4)#?

Answer 1

Domain #x in RR # but #x>=4#
Range #(0,oo)#

#sqrt(x-4)# #x-4>=0# Domain #x in RR # but #x>=4# Range #(0,oo)#
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Answer 2

To find the domain of ( \sqrt{x - 4} ), the expression under the square root must be non-negative, so ( x - 4 \geq 0 ). Solving for ( x ), we get ( x \geq 4 ).

The range of ( \sqrt{x - 4} ) consists of all non-negative real numbers, as the square root of any non-negative real number is non-negative. Therefore, the range is ( [0, +\infty) ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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