How do you find the domain and range of #f(x)= (2x^2+7x-15) / (x+5)#?

Answer 1

#x inRR,y inRR#

#"factorise and simplify by cancelling"#
#f(x)=((2x-3)cancel((x+5)))/cancel(x+5)=2x-3#
#f(x)" simplifies to a linear expression which has no "# #"restrictions on it's domain and hence no restrictions"# #"on it's range"#
#rArr"domain "x inRR#
#rArr"range "y inRR# graph{(2x^2+7x-15)/(x+5) [-10, 10, -5, 5]}
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Answer 2

To find the domain and range of ( f(x) = \frac{2x^2 + 7x - 15}{x + 5} ):

Domain: All real numbers except ( x = -5 ). Range: All real numbers.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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