# How do you find the domain and range of #2x +3y = 12#?

There are no restrictions on the value of

Because this is a linear transformation, the range of this equation or the values of

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To find the domain and range of the equation (2x + 3y = 12), you can solve for (x) in terms of (y) or for (y) in terms of (x). Then, you can determine the possible values of (x) and (y) that satisfy the equation.

Solving for (y) in terms of (x): (3y = 12 - 2x) (y = \frac{12 - 2x}{3}) (y = 4 - \frac{2}{3}x)

Since there are no restrictions on the values (x) can take, the domain of the equation is all real numbers. The range is also all real numbers, as (y) can take any value depending on the value of (x).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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