How do you find the distance between (8,-5), (-1,-3)?
To find the distance between two points, you can use the distance formula. The distance formula is derived from the Pythagorean theorem and is given by:
d = √((x2 - x1)^2 + (y2 - y1)^2)
Using the given points (8, -5) and (-1, -3), we can substitute the values into the formula:
d = √((-1 - 8)^2 + (-3 - (-5))^2)
Simplifying further:
d = √((-9)^2 + (2)^2)
d = √(81 + 4)
d = √85
Therefore, the distance between the points (8, -5) and (-1, -3) is √85.
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See a solution process below:
The formula for calculating the distance between two points is:
Substituting the values from the points in the problem gives:
Or
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To find the distance between two points ((x_1, y_1)) and ((x_2, y_2)) in a coordinate plane, you use the distance formula, which is derived from the Pythagorean theorem:
[d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}]
Given the points ((8, -5)) and ((-1, -3)), plug the coordinates into the formula:
[ d = \sqrt{((-1) - 8)^2 + ((-3) - (-5))^2} \ d = \sqrt{(-9)^2 + (2)^2} \ d = \sqrt{81 + 4} \ d = \sqrt{85} ]
Therefore, the distance between the points ((8, -5)) and ((-1, -3)) is (\sqrt{85}) units.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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