How do you find the distance between (-1,-4), (-6,0)?
To find the distance between two points, (-1,-4) and (-6,0), you can use the distance formula. The distance formula is given by:
d = √((x2 - x1)^2 + (y2 - y1)^2)
Substituting the coordinates, we have:
d = √((-6 - (-1))^2 + (0 - (-4))^2)
Simplifying further:
d = √((-6 + 1)^2 + (0 + 4)^2)
d = √((-5)^2 + (4)^2)
d = √(25 + 16)
d = √41
Therefore, the distance between (-1,-4) and (-6,0) is √41.
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See the entire solution process below:
The formula for calculating the distance between two points is:
Substituting the values from the points in the problem gives:
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To find the distance between two points ((x_1, y_1)) and ((x_2, y_2)) in a Cartesian coordinate system, you can use the distance formula:
[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]
Given the points ((-1, -4)) and ((-6, 0)), you can plug the coordinates into the formula:
[ \text{Distance} = \sqrt{(-6 - (-1))^2 + (0 - (-4))^2} ]
[ = \sqrt{(-6 + 1)^2 + (0 + 4)^2} ]
[ = \sqrt{(-5)^2 + 4^2} ]
[ = \sqrt{25 + 16} ]
[ = \sqrt{41} ]
Therefore, the distance between the points ((-1, -4)) and ((-6, 0)) is (\sqrt{41}) units.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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