How do you find the discriminant and how many solutions does #x^2 + 2x – 2 = 0# have?

Answer 1
For an equation in the general form: #ax^2+bx+c=0# the discriminant is: #Delta = b^2 - 4ac# and #Delta { (<0 rarr "no Real solutions"), (=0 rarr "1 Real solution"), (>0 rarr "2 Real solutions"):}#
For #x^2+2x-2 = 0# #Delta = (2)^2 - 4(1)(-2) = 12 >0# so this equation has 2 Real solutions
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Answer 2
Your equation is in the form: #ax^2+bx+c=0# Where: #a=1# #b=2# #c=-2# The discriminant is: #Delta=b^2-4ac=4-4(1*-2)=4+8=12>0# Now, if: 1] #Delta>0# you have 2 distinct Real solutions; 2] #Delta=0# you have two Real coincident solutions; 3] #Delta<0# you have no Real solutions.
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Answer 3

To find the discriminant of a quadratic equation ( ax^2 + bx + c = 0 ), you use the formula ( b^2 - 4ac ). For the equation ( x^2 + 2x - 2 = 0 ), ( a = 1 ), ( b = 2 ), and ( c = -2 ). Substituting these values into the formula, you get ( 2^2 - 4(1)(-2) = 4 + 8 = 12 ). Since the discriminant is positive (12), the quadratic equation has two distinct real solutions.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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