How do you find the discriminant and how many solutions does #2w^2 - 28w = -98# have?
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To find the discriminant of the quadratic equation (2w^2 - 28w = -98), use the formula for the discriminant, which is (b^2 - 4ac), where (a), (b), and (c) are the coefficients of the quadratic equation.
For this equation: (a = 2), (b = -28), (c = -98).
Plug these values into the discriminant formula:
[\text{Discriminant} = (-28)^2 - 4(2)(-98)]
[\text{Discriminant} = 784 + 784]
[\text{Discriminant} = 1568]
Since the discriminant is positive (1568), there are two distinct real solutions for the quadratic equation.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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