How do you find the discriminant #2x^2+3x-9=0#?

Answer 1

Discriminant is #81#

#2x^2+3x-9=0# Comparing with general quadratic equation #ax^2+bx+c=0 # we get #a=2 ,b= 3 , c= -9# Disciminant is #D=b^2-4ac or D= 3^2 -4 * 2* (-9) = 9 +72 = 81#
If #D >0 # , there is 2 real solution. If #D =0 # , there is 1 real solution. If #D<0 # , there is no real solution , roots are imaginary. Discriminant is #81# [Ans]
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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