# How do you find the differential #dy# of the function #y=(x+1)/(2x-1)#?

The differential of

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To find the differential ( dy ) of the function ( y = \frac{{x + 1}}{{2x - 1}} ), you can differentiate the function with respect to ( x ) using the quotient rule. The quotient rule states that if you have a function of the form ( \frac{{f(x)}}{{g(x)}} ), its derivative is given by:

[ \frac{{d}}{{dx}}\left(\frac{{f(x)}}{{g(x)}}\right) = \frac{{f'(x)g(x) - f(x)g'(x)}}{{[g(x)]^2}} ]

Apply this rule to the function ( y = \frac{{x + 1}}{{2x - 1}} ) to find ( dy ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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