# How do you find the derivatives of #y=ln(x+y)#?

Here's another method.

Hopefully this helps!

By signing up, you agree to our Terms of Service and Privacy Policy

To find the derivative of ( y = \ln(x + y) ) with respect to ( x ), you need to use implicit differentiation.

- Differentiate both sides of the equation with respect to ( x ).
- Apply the chain rule and the derivative of natural logarithm.
- Solve for ( \frac{dy}{dx} ).

The result is:

[ \frac{dy}{dx} = \frac{1}{1 + \frac{dy}{dx}} ]

Rearranging, you get:

[ \frac{dy}{dx} = \frac{1}{1 - \frac{dx}{dy}} ]

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7