How do you find the derivative of #y=(x+8)^5#?
Differentiate u and y
sub u back into the answer.
By signing up, you agree to our Terms of Service and Privacy Policy
To find the derivative of ( y = (x + 8)^5 ), use the power rule for differentiation.
-
Rewrite the function as a power function. ( y = (x + 8)^5 )
-
Apply the power rule: ( \frac{d}{dx}(x^n) = nx^{n-1} ). ( \frac{d}{dx}((x + 8)^5) = 5(x + 8)^{5-1} )
-
Simplify the result. ( \frac{d}{dx}((x + 8)^5) = 5(x + 8)^4 )
Therefore, the derivative of ( y = (x + 8)^5 ) with respect to ( x ) is: [ \frac{d}{dx}((x + 8)^5) = 5(x + 8)^4 ]
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How do you find the derivative of #arctan(x^2y)#?
- How do you implicitly differentiate # y^2+(y-x)^2-y/x^2-3y#?
- How do you differentiate #f(x)=(x-xsinx+1)/(x^2-3x)# using the quotient rule?
- Given #f(x)= x^3 +2x -1#, how do you find #1/ [f^(-1)(2)]#?
- How do you implicitly differentiate #-1=(x+y)^2-xy-e^(3x+7y) #?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7