How do you find the derivative of #y=sin^ntheta#?
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To find the derivative of ( y = \sin^n(\theta) ), where ( n ) is a constant:

Apply the chain rule, which states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function, multiplied by the derivative of the inner function.

Set ( u = \sin(\theta) ).

Rewrite the original function as ( y = u^n ).

Use the power rule for differentiation, which states that the derivative of ( x^n ) with respect to ( x ) is ( nx^{n1} ).

Substitute ( u = \sin(\theta) ) back into the result to obtain the derivative in terms of ( \theta ).
So, the derivative of ( y = \sin^n(\theta) ) with respect to ( \theta ) is ( ny^{(n1)}\cos(\theta) ).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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