How do you find the derivative of #y = s/3 + 5s#?

Answer 1
I think you need the derivative with respect to #s# which is a simple variable (not a function of anothe one). With this in mind you use the normal Rules of Derivation giving you: #y'=1/3+5=16/3#

Hope it helps

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Answer 2

To find the derivative of ( y = \frac{s}{3} + 5s ), you apply the rules of differentiation. In this case, since ( s ) is the variable, you differentiate each term with respect to ( s ). The derivative of ( \frac{s}{3} ) is ( \frac{1}{3} ) and the derivative of ( 5s ) is ( 5 ). So, the derivative of ( y ) with respect to ( s ) is ( \frac{1}{3} + 5 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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