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How do you find the derivative of #y=ln(x^2)#?

Answer 1

You much use the chain rule to solve this problem

#y=ln(x^2)#

#y'= 1/x^2*2x#

#y'= (2x)/x^2=2/x->#Solution

Or you could use one of the properties of logarithms where you can pull the power to the front of the expression as a factor.

#y=ln(x^2)=2ln(x)#

#y'= 2*1/x=2/x ->#Solution

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Answer 2

Christopher Allers

The derivative of ( y = \ln(x^2) ) is ( \frac{dy}{dx} = \frac{2x}{x^2} = \frac{2}{x} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.