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How do you find the derivative of #y=ln(x^2+1)#?

Answer 1

Emma Aldridge

By Chain Rule,

#y'=1/{x^2+1}cdot(x^2+1)'={2x}/{x^2+1}#

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Answer 2

Cameron Alexander

To find the derivative of ( y = \ln(x^2 + 1) ), use the chain rule. The derivative is:

[ \frac{dy}{dx} = \frac{1}{x^2 + 1} \cdot 2x = \frac{2x}{x^2 + 1} ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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