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How do you find the derivative of #y=[e^(-2x)][1 + e^(-2x)]^(-1/2)#?

Answer 1

Christopher Allers

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Answer 2

Axel Alvarez

To find the derivative of y=[e^(-2x)][1 + e^(-2x)]^(-1/2), you can use the product rule and the chain rule. The derivative is: y' = -2e^(-2x)[1 + e^(-2x)]^(-1/2) - e^(-2x)(-1/2)(1 + e^(-2x))^(-3/2)(-2)e^(-2x).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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