How do you find the derivative of #y=arcsin(2x+1)#?
Note that:
So, according to the chain rule:
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To find the derivative of ( y = \arcsin(2x + 1) ), you can use the chain rule of differentiation. The derivative is ( \frac{d}{dx} \arcsin(u) = \frac{1}{\sqrt{1-u^2}} \cdot \frac{du}{dx} ). Applying this rule, the derivative of ( y ) with respect to ( x ) is ( \frac{2}{\sqrt{1 - (2x + 1)^2}} ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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