How do you find the derivative of #y=5/(2x)^2+2cosx#?
Once we rewrite, we will need the rules:
So first we see that
So then
By signing up, you agree to our Terms of Service and Privacy Policy
To find the derivative of ( y = \frac{5}{(2x)^2} + 2\cos(x) ), apply the quotient rule and the chain rule for differentiation. The derivative is ( y' = -\frac{20}{(2x)^3} - 2\sin(x) ).
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How do you differentiate #f(x)= ( x - 2)/ ( sin x )# using the quotient rule?
- How do you use the chain rule to differentiate #y=(x^2+3x)^(-1/2)#?
- How do you find the derivative of #s(t)=t^3-2t+4#?
- How do you use implicit differentiation to find dy/dx given #xy^2+x^2y=x#?
- How do you implicitly differentiate #-y=x-sqrt(x^3y-y) #?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7