# How do you find the derivative of #y=2x^2-7#, where x=-2?

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To find the derivative of ( y = 2x^2 - 7 ) at ( x = -2 ), we first differentiate the function with respect to ( x ) using the power rule, then evaluate the derivative at ( x = -2 ).

The derivative of ( y = 2x^2 - 7 ) is ( \frac{dy}{dx} = 4x ).

Substituting ( x = -2 ) into the derivative expression, we get ( \frac{dy}{dx} = 4(-2) = -8 ). Therefore, the derivative of ( y = 2x^2 - 7 ) at ( x = -2 ) is ( -8 ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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