# How do you find the derivative of # y = (2cosx)/(x+1)#?

Now, applying the quotient rule to the function, we get:

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To find the derivative of ( y = \frac{2\cos(x)}{x+1} ), use the quotient rule: ((f/g)' = (f'g - fg') / g^2), where ( f = 2\cos(x) ) and ( g = x + 1 ).

( f' = -2\sin(x) ) (derivative of ( 2\cos(x) )) and ( g' = 1 ) (derivative of ( x + 1 )).

So, ( y' = \frac{(-2\sin(x))(x + 1) - (2\cos(x))(1)}{(x + 1)^2} = \frac{-2x\sin(x) - 2\sin(x) - 2\cos(x)}{(x + 1)^2} ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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