# How do you find the derivative of #(tanx)^-1#?

I would rewrite the function before differentiating

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To find the derivative of ((\tan(x))^{-1}), you can use the chain rule. Let (y = (\tan(x))^{-1}). Then, differentiate (y) with respect to (x), and apply the chain rule.

[\frac{dy}{dx} = -\frac{1}{(\tan(x))^2} \cdot \sec^2(x)]

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