How do you find the derivative of #sin (2x+3)#?
I tried this:
I would use the Chain Rule:> deriving the argument (red) and then the sine (blue):
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To find the derivative of sin(2x+3), use the chain rule. The derivative of sin(u) with respect to u is cos(u). Then, multiply by the derivative of the inside function (2x+3) with respect to x, which is 2. So, the derivative of sin(2x+3) is cos(2x+3) * 2, which simplifies to 2cos(2x+3).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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