How do you find the derivative of #-sin^2(x)#?

Answer 1

#-2sin(x)cos(x)#

Use the chain rule.

#d/dx[-sin^2(x)]=-2sin(x)d/dx[sin(x)]=-2sin(x)cos(x)#
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Answer 2

To find the derivative of ( -\sin^2(x) ), you can use the chain rule and the derivative of the sine function. First, differentiate the outer function, which is the square function, and then multiply it by the derivative of the inner function, which is (-\sin(x)).

The derivative of (-\sin^2(x)) is:

[ -2\sin(x)\cos(x) ]

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Answer 3

To find the derivative of -sin^2(x), you can use the chain rule of differentiation.

First, differentiate the outer function, which is the negative sign, resulting in -1. Then, differentiate the inner function, sin^2(x), using the chain rule.

The derivative of sin^2(x) is 2sin(x)cos(x), which comes from applying the chain rule to the square of the sine function.

Finally, multiply the derivatives of the outer and inner functions together to obtain the derivative of -sin^2(x).

So, the derivative of -sin^2(x) is -1 * 2sin(x)cos(x) = -2sin(x)cos(x).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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