# How do you find the derivative of #ln((x+1)/(x-1))#?

I rewrite it first.

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To find the derivative of ln((x+1)/(x-1)), you can use the chain rule and the quotient rule. The derivative is:

d/dx [ln((x+1)/(x-1))] = (1/((x+1)/(x-1))) * (1/(x+1)) * (d/dx(x+1) - d/dx(x-1)) = (1/((x+1)/(x-1))) * (1/(x+1)) * (1 - (-1)/(x-1))^2

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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