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How do you find the derivative of #ln((sin^2)x) #?

Answer 1

Emma Aldridge

#d/(dx) ln(sin^2(x)) =2 cot(x)#

#d/(dx) ln(sin^2(x)) = (d/(dx)sin^2(x))/(sin^2(x))=(2 sin(x) cos(x))/(sin^2(x))=(2 cos(x))/(sin(x))#

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Answer 2

Aurora Alvarado

To find the derivative of ln((sin^2)x), you apply the chain rule. The derivative is (2 * sin(x) * cos(x)) / sin^2(x).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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