How do you find the derivative of #ln(secx + tanx)#?

Answer 1

You can solve the problem by using implicit differentiation...

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Answer 2

To find the derivative of ln(secx + tanx), you can use the chain rule. The derivative is:

d/dx[ln(secx + tanx)] = (1 / (secx + tanx)) * (d/dx[secx + tanx])

Now, apply the derivatives of secx and tanx:

d/dx[secx + tanx] = secx*tanx + sec^2(x)

Substitute this back into the expression:

d/dx[ln(secx + tanx)] = (1 / (secx + tanx)) * (secx*tanx + sec^2(x))

Simplify if necessary, but this is the derivative of ln(secx + tanx).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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