# How do you find the derivative of Inverse trig function #y= arctan(x - sqrt(1+x^2))#?

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Note: (Formulas)

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To find the derivative of the inverse trigonometric function ( y = \arctan(x - \sqrt{1+x^2}) ), we differentiate with respect to ( x ) using the chain rule and derivative of inverse trigonometric functions.

[ y' = \frac{1}{1 + (x - \sqrt{1+x^2})^2} \cdot (1 - \frac{x}{\sqrt{1+x^2}}) ]

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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