# How do you find the derivative of Inverse trig function #y=arcsec(1/x) #?

Now the Chain Rule implies:

Try graphing them both to check this!

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To find the derivative of the inverse trigonometric function ( y = \text{arcsec}(1/x) ), you can use the chain rule, which states that the derivative of a composition of functions is the derivative of the outer function evaluated at the inner function, multiplied by the derivative of the inner function.

So, for ( y = \text{arcsec}(1/x) ), the derivative is:

[ \frac{dy}{dx} = -\frac{1}{x \cdot |x| \cdot \sqrt{x^2 - 1}} ]

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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