How do you find the derivative of #f(y)=2y^3+4y^2#?

Answer 1

#f'(y)=6y^2+8y#

The question might seem strange because we are used to seeing functions defined in terms of some variable "#x#". But we can use any other letter, and it still works the same way.

Finding the derivative of #f(y)# with respect to #y# is exactly the same as finding the derivative of #f(x)# with respect to #x#.

#f(y)=2y^3+4y^2#

Multiply the coefficient of each term by the exponent of #y#, then lower the exponent by 1.

#f'(y)=3*2y^(3-1)+2*4y^(2-1)#

#f'(y)=6y^2+8y#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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