# How do you find the derivative of #f(y)=2y^3+4y^2#?

By signing up, you agree to our Terms of Service and Privacy Policy

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7

Homework Q&A

Tools

Answer 1

The question might seem strange because we are used to seeing functions defined in terms of some variable "#x#". But we can use any other letter, and it still works the same way.

Finding the derivative of #f(y)# with respect to #y# is exactly the same as finding the derivative of #f(x)# with respect to #x#.

#f(y)=2y^3+4y^2#

Multiply the coefficient of each term by the exponent of #y#, then lower the exponent by 1.

#f'(y)=3*2y^(3-1)+2*4y^(2-1)#

#f'(y)=6y^2+8y#

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email

Answer from HIX Tutor

Trending questions

Not the question you need?

HIX Tutor

Solve ANY homework problem with a smart AI

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7