How do you find the derivative of #f(x)=5(3x^2+5x+1)#?
By signing up, you agree to our Terms of Service and Privacy Policy
To find the derivative of ( f(x) = 5(3x^2 + 5x + 1) ), you can use the power rule and constant multiple rule. Here's the stepbystep process:

Use the constant multiple rule: Multiply the constant (5) by the derivative of the expression inside the parentheses. [ f'(x) = 5 \cdot \frac{d}{dx}(3x^2 + 5x + 1) ]

Find the derivative of each term inside the parentheses using the power rule: [ \frac{d}{dx}(3x^2 + 5x + 1) = 6x + 5 ]

Substitute the derivative back into the equation: [ f'(x) = 5(6x + 5) ]

Distribute the constant (5) to each term inside the parentheses: [ f'(x) = 30x + 25 ]
So, the derivative of ( f(x) = 5(3x^2 + 5x + 1) ) is ( f'(x) = 30x + 25 ).
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
 98% accuracy study help
 Covers math, physics, chemistry, biology, and more
 Stepbystep, indepth guides
 Readily available 24/7