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How do you find the derivative of # f(x) = 3xsin(2x)^2#?

Answer 1

Emma Aldridge

#(df(x))/(dx)=3sin(2x)^2+24x^2cos(2x)^2#

To find the derivative of #f(x)=3xsin(2x)^2#, we use poduct formula and chain rule.

#(df(x))/(dx)=1xx3sin(2x)^2+3x xxcos(2x)^2xx8x#

= #3sin(2x)^2+24x^2cos(2x)^2#

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Answer 2

Adam Adkins

To find the derivative of f(x) = 3xsin(2x)^2, you would apply the product rule and chain rule. The derivative is:

f'(x) = 3sin(2x)^2 + 12xsin(2x)cos(2x).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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