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How do you find the derivative of #f(x)= 3cos(2x) + sin(2x)#?

Answer 1

You can use the Chain Rule to deal with the arguments of #cos# and #sin# deriving first the trigonometric function as it is and then multiply by the derivative of the argument getting:

#f'(x)=[-3sin(2x)]*2+[cos(2x)]*2=#

#=-6sin(2x)+2cos(2x)#

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Answer 2

Cameron Alexander

To find the derivative of ( f(x) = 3\cos(2x) + \sin(2x) ), use the chain rule and the derivatives of sine and cosine functions. The derivative is ( f'(x) = -6\sin(2x) + 2\cos(2x) ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.