How do you find the derivative of #f(x)=2-5x#?

Answer 1

-5

When taking derivatives, you can ignore constants without an #x#. When there is an #x# raised to the first power, then the derivative is just the coefficient in front.

Check out the power rule for more detail:

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Answer 2

#-5#

Using the power rule:

#f(x)=x^n -> f'(x)=nxxx^(n-1)#
#d/dx (2-5x) #
#=d/dx(2^1-5x^1)#
Anything without an #x# will always give #0# when deriving.
#-> -5#
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Answer 3

To find the derivative of ( f(x) = 2 - 5x ), you can use the power rule of differentiation, which states that if you have a function of the form ( f(x) = ax^n ), the derivative is ( f'(x) = n \cdot ax^{n-1} ). Applying this rule, the derivative of ( f(x) = 2 - 5x ) is ( f'(x) = -5 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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