How do you find the derivative of #f(x)= 1/x^2#?

Answer 1

#f'(x)=-2/x^3#

Rewrite the function with negative exponents, recalling that #1/x^a=x^-a#:
#f(x)=x^-2#
Apply the Power Rule, which tells us that if #f(x)=x^n, f'(x)=nx^(n-1):#
#f'(x)=-2x^(-2-1)#
#f'(x)=-2x^-3#
#f'(x)=-2/x^3#
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Answer 2

To find the derivative of ( f(x) = \frac{1}{x^2} ), you can use the power rule for differentiation. The power rule states that if you have a function of the form ( f(x) = x^n ), then its derivative is ( f'(x) = nx^{n-1} ). Applying this rule to ( f(x) = \frac{1}{x^2} ), you get:

[ f'(x) = -2x^{-2-1} = -2x^{-3} = \frac{-2}{x^3} ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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