How do you find the derivative of #1 + tanx#?

Question

Charles Arocha · Accepted Answer

As differentiation is linear:

#d/dx (1+tanx) = d/dx (1) + d/dx (tanx) = 0+1/cos^2x= 1/cos^2x#

Cameron Alexander · Answer

undefined To findTo find theTo find the derivative of $1 + \tan(x)$, weTo find the derivative of $1 + \tan(x)$, youTo find the derivative of $1 + \tan(x)$, we useTo find the derivative of $1 + \tan(x)$, you applyTo find the derivative of $1 + \tan(x)$, we use theTo find the derivative of $1 + \tan(x)$, you apply theTo find the derivative of $1 + \tan(x)$, we use the chainTo find the derivative of $1 + \tan(x)$, you apply the rulesTo find the derivative of $1 + \tan(x)$, we use the chain ruleTo find the derivative of $1 + \tan(x)$, you apply the rules ofTo find the derivative of $1 + \tan(x)$, we use the chain rule.To find the derivative of $1 + \tan(x)$, you apply the rules of differentiationTo find the derivative of $1 + \tan(x)$, we use the chain rule. TheTo find the derivative of $1 + \tan(x)$, you apply the rules of differentiation.To find the derivative of $1 + \tan(x)$, we use the chain rule. The derivativeTo find the derivative of $1 + \tan(x)$, you apply the rules of differentiation. TheTo find the derivative of $1 + \tan(x)$, we use the chain rule. The derivative ofTo find the derivative of $1 + \tan(x)$, you apply the rules of differentiation. The derivativeTo find the derivative of $1 + \tan(x)$, we use the chain rule. The derivative of \To find the derivative of $1 + \tan(x)$, you apply the rules of differentiation. The derivative ofTo find the derivative of $1 + \tan(x)$, we use the chain rule. The derivative of $\To find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $To find the derivative of \(1 + \tan(x)$, we use the chain rule. The derivative of $\tanTo find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1To find the derivative of \(1 + \tan(x)$, we use the chain rule. The derivative of $\tan(xTo find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$To find the derivative of $1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)\To find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ isTo find the derivative of $1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$To find the derivative of $1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $To find the derivative of \(1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ isTo find the derivative of $1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0To find the derivative of \(1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is \To find the derivative of $1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0\To find the derivative of \(1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\To find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$,To find the derivative of $1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\secTo find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, andTo find the derivative of $1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^To find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and theTo find the derivative of $1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2To find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivativeTo find the derivative of $1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(xTo find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative ofTo find the derivative of $1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)\To find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of \To find the derivative of $1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$.To find the derivative of $1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\To find the derivative of \(1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. ThereforeTo find the derivative of $1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tanTo find the derivative of \(1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore,To find the derivative of $1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(xTo find the derivative of \(1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore, theTo find the derivative of $1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(x)$To find the derivative of $1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore, the derivativeTo find the derivative of $1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(x)$ isTo find the derivative of $1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore, the derivative ofTo find the derivative of $1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(x)$ is $To find the derivative of \(1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore, the derivative of $To find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(x)$ is $ \To find the derivative of \(1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore, the derivative of $1To find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(x)$ is $ \secTo find the derivative of \(1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore, the derivative of $1 + \To find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(x)$ is $ \sec^To find the derivative of \(1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore, the derivative of $1 + \tanTo find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(x)$ is $ \sec^2To find the derivative of \(1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore, the derivative of $1 + \tan(xTo find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(x)$ is $ \sec^2(xTo find the derivative of \(1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore, the derivative of $1 + \tan(x)\To find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(x)$ is $ \sec^2(x)To find the derivative of \(1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore, the derivative of $1 + \tan(x)$To find the derivative of $1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(x)$ is $ \sec^2(x) \To find the derivative of \(1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore, the derivative of $1 + \tan(x)$ isTo find the derivative of $1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(x)$ is $ \sec^2(x) $.To find the derivative of $1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore, the derivative of $1 + \tan(x)$ is $To find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(x)$ is $ \sec^2(x) $. ThusTo find the derivative of $1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore, the derivative of $1 + \tan(x)$ is $0To find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(x)$ is $ \sec^2(x) $. Thus,To find the derivative of $1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore, the derivative of $1 + \tan(x)$ is $0 +To find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(x)$ is $ \sec^2(x) $. Thus, theTo find the derivative of $1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore, the derivative of $1 + \tan(x)$ is $0 + \To find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(x)$ is $ \sec^2(x) $. Thus, the derivativeTo find the derivative of $1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore, the derivative of $1 + \tan(x)$ is $0 + \secTo find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(x)$ is $ \sec^2(x) $. Thus, the derivative ofTo find the derivative of $1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore, the derivative of $1 + \tan(x)$ is $0 + \sec^To find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(x)$ is $ \sec^2(x) $. Thus, the derivative of $To find the derivative of \(1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore, the derivative of $1 + \tan(x)$ is $0 + \sec^2To find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(x)$ is $ \sec^2(x) $. Thus, the derivative of $1To find the derivative of \(1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore, the derivative of $1 + \tan(x)$ is $0 + \sec^2(xTo find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(x)$ is $ \sec^2(x) $. Thus, the derivative of $1 +To find the derivative of \(1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore, the derivative of $1 + \tan(x)$ is $0 + \sec^2(x)\To find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(x)$ is $ \sec^2(x) $. Thus, the derivative of $1 + \tan(x)\To find the derivative of \(1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore, the derivative of $1 + \tan(x)$ is $0 + \sec^2(x)$, which simplifies to $\sec^2(xTo find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(x)$ is $ \sec^2(x) $. Thus, the derivative of $1 + \tan(x)$ isTo find the derivative of $1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore, the derivative of $1 + \tan(x)$ is $0 + \sec^2(x)$, which simplifies to $\sec^2(x)\To find the derivative of \(1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(x)$ is $ \sec^2(x) $. Thus, the derivative of $1 + \tan(x)$ is $ \sec^2(x)To find the derivative of \(1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore, the derivative of $1 + \tan(x)$ is $0 + \sec^2(x)$, which simplifies to $\sec^2(x)$.To find the derivative of $1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(x)$ is $ \sec^2(x) $. Thus, the derivative of $1 + \tan(x)$ is $ \sec^2(x) \To find the derivative of \(1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore, the derivative of $1 + \tan(x)$ is $0 + \sec^2(x)$, which simplifies to $\sec^2(x)$.To find the derivative of $1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(x)$ is $ \sec^2(x) $. Thus, the derivative of $1 + \tan(x)$ is $ \sec^2(x) $.To find the derivative of $1 + \tan(x)$, we use the chain rule. The derivative of $\tan(x)$ is $\sec^2(x)$. Therefore, the derivative of $1 + \tan(x)$ is $0 + \sec^2(x)$, which simplifies to $\sec^2(x)$.To find the derivative of $1 + \tan(x)$, you apply the rules of differentiation. The derivative of $1$ is $0$, and the derivative of $\tan(x)$ is $ \sec^2(x) $. Thus, the derivative of $1 + \tan(x)$ is $ \sec^2(x) $.